How do you multiply #(n-4)(n+1)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Lucy May 11, 2018 #n^2-3n-4# Explanation: #(n-4)(n+1)# =#n(n+1)-4(n+1)# =#n^2+n-4n-4# =#n^2-3n-4# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 2200 views around the world You can reuse this answer Creative Commons License