How do you multiply #(2x-3)(x^4-2x^2+3)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Mark D. May 13, 2018 #2x^5-3x^4-4x^3+6x^2+6x-9# Explanation: Multiply each term in the second bracket by #2x# and then multiply each term by -3. #(2x-3)(x^4-2x^2+3)# #2x^5-4x^3+6x-3x^4+6x^2-9# #2x^5-3x^4-4x^3+6x^2+6x-9# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 3382 views around the world You can reuse this answer Creative Commons License