How do you solve $3 x - 7 > 5$ $3x-7>5$ ?

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Answer 1 · 2018-05-14T03:35:27

$x > 4$ $x > 4$

Solving inequalities is similar to solving equations.

First, we want to add $7$ $color(blue)7$ to both sides of the inequality:
$3x - 7 quadcolor(blue)(+quad7) > 5 quadcolor(blue)(+quad7)$

$3x > 12$

Now divide both sides by $color(blue)3$ :
$(3x)/color(blue)3 > 12/color(blue)3$

So the answer is:
$x > 4$

This is the same thing as " $x$ is greater than $4$ ".

Hope this helps!

Answer 2 · 2018-05-14T03:38:37

The answer is:
$x > 4$

$3x - 7 > 5$

Let's make it look simpler by isolating the x-base value.

We can add 7 on both sides to eliminate 7 on LHS

$3x - 7 + 7 > 5 + 7$
$or, 3x > 12$

Dividing both side by 3:

$or, (3x)/3 > 12/3$
$or, x > 4$

How do you solve 3x-7>53x−7>53x-7>5?