What is the vertex of #y= 4(x-2)^2-12 #?

1 Answer
May 14, 2018

#"vertex "=(2,-12)#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#

#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#

#y=4(x-2)^2-12" is in vertex form"#

#"with "h=2" and "k=-12#

#rArrcolor(magenta)"vertex "=(2,-12)#