How do you factor $45 m^{4} + 18 m^{2} n^{2} - 8 m n^{2}$ $45m^4 + 18m^2n^2 - 8mn^2$ ?

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Answer 1 · 2018-05-15T19:09:28

$m (45 m^{3} + 18 m n^{2} - 8 n^{2})$ $m(45m^3+18mn^2-8n^2)$

Factor out the m by dividing each term by m.

$m (45 m^{3} + 18 m n^{2} - 8 n^{2})$ $m(45m^3+18mn^2-8n^2)$

Nothing else can be done to factor this expression with rational numbers.

How do you factor 45m4+18m2n2−8mn245m^4 + 18m^2n^2 - 8mn^2?