How do you factor #10x^2 - 8x - 15x + 12#?

1 Answer
Jim G.
May 16, 2018

#(2x-3)(5x-4)#

Explanation:

#"if the ratios of the coefficients of the first/second terms"#
#"and third/fourth terms are equal we can factor by grouping"#

#"As they stand this is not the case but rearranging gives"#

#10x^2-15x-8x+12larrcolor(blue)"factor by grouping"#

#=color(red)(5x)(2x-3)color(red)(-4)(2x-3)#

#"take out the "color(blue)"common factor "(2x-3)#

#=(2x-3)(color(red)(5x-4))#

#rArr10x^2-8x-15x+12=(2x-3)(5x-4)#

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