What is the vertex of y=3(x - 2)^2 + 5 ?

1 Answer
May 16, 2018

vertex: (2, 5)

Explanation:

y = 3(x-2)^2+5

this is a parabola because of one variable squared and the other one is not so now write it in the standard form of parabolas which it is = to

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Vertical :

(x-h)^2=4p(y-k)

Horizontal:

(y-k)^2=4p(x-h)^2

vertex = (h, k)

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this y=3(x-2)^2+5 equation is vertical since x is squared

subtract 5 from both sides:

y-5=3(x-2)^2

divide both sides by 3:

(y-5)1/3=(x-2)^2

vertex:

(2, 5)