How do you factor $x^{2} + 8 x + 16 - y^{2}$ $x^2 + 8x + 16 - y^2$ ?

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Answer 1 · 2018-05-16T18:52:43

$(x + 4 + y) \cdot (x + 4 - y)$ $(x+4+y)*(x+4-y)$

$x^{2} + 8 x + 16 - y^{2}$ $x^2+8x+16-y^2$

= ${(x + 4)}^{2} - y^{2}$ $(x+4)^2-y^2$

= $(x + 4 + y) \cdot (x + 4 - y)$ $(x+4+y)*(x+4-y)$

How do you factor x2+8x+16−y2x^2 + 8x + 16 - y^2 ?