First, add #color(red)(1)# and subtract #color(blue)(3n)# from each side of the inequality to isolate the #n# term while keeping the equation balanced:
#7n - color(blue)(3n) - 1 + color(red)(1) < 3n - color(blue)(3n) + 5 + color(red)(1)#
#(7 - color(blue)(3))n - 0 < 0 + 6#
#4n < 6#
Now, divide each side of the inequality by #color(red)(4)# to solve for #n# while keeping the inequality balanced:
#(4n)/color(red)(4) < 6/color(red)(4)#
#(color(red)(cancel(color(black)(4)))n)/cancel(color(red)(4)) < 3/2#
#n < 3/2#
To graph this on a number line we put a hollow circle at #3/2#. The circle is hollow because there is no "or equality to" clause in the inequality operator.
We draw a line from #3/2# to the left because the inequality operator is a "less than" clause.
