How do you solve #tan 4x = tan 2x#?

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Answer 1 · 2018-05-08T07:25:35

#rarrx=(npi)/2# where #nrarrZ#

#rarrtan4x=tan2x#

#rarr4x=npi+2x#

#rarr2x=npi#

#rarrx=(npi)/2# where #nrarrZ#

NOTE THAT If #tanx=tanalpha# then #x=npi+alpha# where #n in ZZ#

Answer 2 · 2018-05-18T05:23:43

#rarrtan4x=tan2x#

#rarrtan4x-tan2x=0#

#rarr(tan4x-tan2x)/(1+tan4x*tan2x)=0/(1+tan4x*tan2x)#

#rarrtan(4x-2x)=0#

#rarrtan2x=0#

#rarr2x=npi#

#rarrx= (npi)/2# where #n in ZZ#