How do you write an equation of a line with point (2,5), slope -2?

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Answer 1 · 2018-05-19T04:27:32

both answers:

#y−5=-2(x−2)#

and

#y=-2x +9#

are correct.

Point slope form of a line is the standard equation:

#y−y_1=m(x−x_1)#

where #x_1# and #y_1# are a point the line intersects and #m# in the slope, so your line:

#y−5=-2(x−2)# is your line.

you can convert it to slope intercept form:

#y=-2x +9#

so the slope #m =-2# and the y-intercept is 9

graph{y=-2x +9 [-17.04, 22.96, -5.36, 14.64]}

Answer 2 · 2018-05-19T04:29:52

#y=-2x+9#

We must assume that the line is a straight line.

The equation of a straight line in slope/point form is:

#(y-y_1) = m(x-x_1)#

Where the line has a slope #m# and passes through the point #(x_1,y_1)#

Here we have a line of slope #-2# passing through the point #(2,5)#

#:. (y-5) = -2(x-2)#

#y = -2x+4+5#

#y=-2x+9#
is the equation of the line in slope/intercept form.