Question

How many valence electrons does `F` have?

Answer 1

`7`

Explanation:

Fluorine's electron configuration is:

`[He]2s^2\2p^5` or `1s^2\2s^2\2p^5`

Therefore, its valence shell is `n=2`, and so it contains `2+5=7` valence electrons. Since it is one electron away from achieving an electron configuration of neon, a noble gas, would you expect fluorine to have high electronegativity or not?