Question

How do you find the point (x,y) on the unit circle that corresponds to the real number `t=(5pi)/4`?

Answer 1

M`(-sqrt2/2, - sqrt2/2)`

Explanation:

`t = pi/4 + pi`. --> t is in Quadrant 3
`x = cos t = - cos (pi/4) = - sqrt2/2`
`y = sin t = - (sin pi/4) = - sqrt2/2`
Point M(x, y) has as coordinates:
M`(-sqrt2/2, - sqrt2/2)`