What is the equation of the line with slope # m= 8/49 # that passes through # (2/7, 1/21) #?

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Answer 1 · 2018-05-27T13:54:08

#color(indigo)(168x - 1029y + 1 = 0#

Point-Slope equation form is

#(y - y_1) = m * (x - x _1)#

#y - (1/21) = (8/49) * (x - (2/7))#

#(21y -1) / cancel(21)^color(red)(3)= (56x - 16) / (49 * cancel7)#

#(21y - 1) * 49 = 3 * (56x - 16)#

#1029y - 49 = 168x - 48#

#color(indigo)(168x - 1029y + 1 = 0#

Answer 2 · 2018-05-27T17:37:35

Shown below...

If you are unfamiliar with #y- y_1 = m ( x - x_1 ) #

Use #y= mx + c #

#=> y = 8/49 x + c#

Now find #c# by subbing in # x = 2/7 # and # y = 1/21 #

#=> 1/21 = ( 8/49 * 2/7 ) + c #

#=> 1/21 = 16/343 + c #

# => c= 1/21 - 16/343 #

#=> c = 1/1029 #

#=> y = 8/49 x + 1/1029 #

Both solutions are valid for this