What is the vertex form of #y= -25x^2 + 8x - 13 #?

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Answer 1 · 2018-05-28T12:32:49

Vertex form of equation is #y = -25 (x-0.16)^2-12.36 #

#y = -25 x^2+8 x -13# or

#y = -25 (x^2-8/25 x) -13# or

#y = -25 {x^2-8/25 x + (4/25)^2}+25 *16/625 -13# or

#y = -25 (x-4/25)^2+16/25 -13# or

#y = -25 (x-4/25)^2-309/25# or

#y = -25 (x-0.16)^2-12.36 :. # Vertex is at

#(0.16 , -12.36)# and vertex form of equation is

#y = -25 (x-0.16)^2-12.36 # [Ans]