Question

How do you solve the system of equations algebraically `4x+5y=-8, 3x-7y=10`?

Answer 1

`x=-6/43,y=-64/43`

Explanation:

Multiplying the first equation by `7` and the second by `5` and adding we get
`43x=-6` so
`x=-6/43`
Plugging this in the first equation we get
`5*(-6/43)+5y=-8`
so
`5y=-8+24/43`
`y=-64/43`