Question

What is the distance between `(-6, -6)` and # (4,0) #?

Answer 1

The distance is `2sqrt34` or about `11.66`.

Explanation:

The distance between two points is shown by the formula:
`d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)`

We have the values for the two coordinates, so we can substitute them into the distance formula:
`d = sqrt((0-(-6))^2 + (4-(-6))^2)`

And now we simplify:
`d = sqrt((6)^2 + (10)^2)`

`d = sqrt(36 + 100)`

`d = sqrt(136)`

`d = sqrt(4*34)`

`d = sqrt4sqrt34`

`d = 2sqrt34`

If you want the exact distance, you can leave it as `2sqrt34`, but if you want it in decimal form, it is `~~11.66` (rounded to nearest hundredth's place).

Hope this helps!