How do you find three consecutive odd integers such that the sum of the largest and twice the smallest is 25?

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Answer 1 · 2018-05-30T00:56:45

#=>7,9,11#

Let the smallest consecutive odd number be #n#. Then the next two consecutive odd integers are #n+2# and #n+4#.

"Sum of the largest and twice the smallest is #25#"

#(n+4) + 2(n) = 25#

#n+4+2n = 25#

#3n+4=25#

#3n = 21#

#=>n = 7#

So the three numbers (#n#, #n+2#, #n+4#) are: #7, 9, 11#