What is the square root of a^2\b^5?

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Answer 1 · 2018-05-30T19:28:01

#=(asqrtb)/(b^3)#

I assume you meant:

#=sqrt(a^2/b^5)#

#=sqrt(a^2)/sqrt(b^5)#

#=a/(b^2sqrt(b))#

now you need to rationalize the denominator by multiplying the expression by:

#sqrtb/sqrtb#

#=a/(b^2sqrt(b))*sqrtb/sqrtb#

#=(asqrtb)/(b^2*b)#

#=(asqrtb)/(b^3)#

Answer 2 · 2018-05-30T19:34:04

#(a sqrt b)/b^3#

#sqrt(a^2/b^5)#

#:.=sqrt (a^2)/sqrt (b^5)#

#:.=(sqrt (a*a))/sqrt (b*b*b*b*b)#

#:.sqrt (a)*sqrt (a)=a#

#:.sqrt (b)*sqrt (b)=b#

#:.=a/(b^2 sqrt b) xx(b^2sqrtb)/(b^2sqrtb)#

#:.=(ab^2 sqrt b)/b^5#

#:.=(a sqrt b)/b^(5-2)#

#:.=(a sqrt b)/b^3#