What is the y intercept of the line #x-y=12 #?

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Answer 1 · 2018-06-01T00:46:49

#y= -12#

#m=1#

Put it in slope intercept form:

#x-y=12#

#-y=-x+12#

#y=x-12#

So the y-intercept is #-12#

graph{x-12 [-16.79, 23.21, -17, 3]}

Answer 2 · 2018-06-01T02:22:35

#y=-12#

The point for the y-intercept is #(0,-12)#.

Given:

#x-y=12#

This equation is the standard form for a linear equation: #Ax+By=C#

The y-intercept is the value of #y# when #x=0#.

Substitute #0# for #x# and solve for #y#.

#0-y=12#

#-y=12#

Divide both sides by #-1#. This will reverse the signs.

#y=-12#

The point for the y-intercept is #(0,-12)#.

graph{x-y=12 [-16.23, 15.8, -14.85, 1.17]}