How do you find the amplitude, period, phase shift given $y=1-tan(3pi+2x)$ ?

Question

1861 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-01T03:23:53

See below.

Standard form of tangent function is

$y = - tan (2x + 3pi) + 1$

Amplitude - None

Period $= pi / |B| = pi / 2$

Phase Shift $= -C / B = -(3pi) / 2$ , $(3pi)/2$ to the left.

Vertical Shift $= D = 1$

How do you find the amplitude, period, phase shift given y=1-tan(3pi+2x)y=1-tan(3pi+2x)?