Two rhombuses have sides with lengths of #5 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #(3pi)/4 #, what is the difference between the areas of the rhombuses?

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Answer 1 · 2018-06-01T13:27:37

Diff. between areas of the rhombuses = 11.21#

Area of Rhombus #A_r = a^2 sin theta#

#a= 5, theta_1 = pi/12, theta_2 = (3pi)/4#

#A_(r1) = 5^2 * sin (pi/12) = 6.47#

#A_(r2) = 5^2 * sin ((3pi)/4) = 17.68#

Diff. between the rhombuses = 17.68 - 6.47 = 11.21#