What is the distance between #(5, –1)# and # (-4, 6) #?

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Answer 1 · 2018-06-06T02:31:16

#d = sqrt(130)#

Distance:

#d = sqrt((y_2-y_1)^2+(x_2-x_1)^2)#

We have:

#(x_1,y_1) = (5,-1)#

and

#(x_2,y_2) = (-4,6)#

This gives us a distance of

#d = sqrt((6-(-1))^2+(-4-5)^2)#

#d = sqrt((7)^2+(-9)^2)#

#d = sqrt(49+81)#

#d = sqrt(130)#