How do you solve #5x + 4< 3( 5x - 2)#?
1 Answer
Jun 6, 2018
Explanation:
#"distribute the bracket on the right side"#
#5x+4<15x-6#
#"collect terms in x on one side and numeric values on"#
#"the other side"#
#"subtract "5x" from both sides"#
#cancel(5x)cancel(-5x)+4<15x-5x-6#
#4<10x-6#
#"add 6 to both sides"#
#4+6<10x#
#10<10x#
#"divide both sides by 10"#
#1< x" or "x>1#
