How do you find the product [(t^2+3t-8)-(t^2-2t+6)](t-4)?

1 Answer
Jun 6, 2018

[(t^2+3t-8)-(t^2-2t+6)] (t-4) = 5t^2-34t+56

Explanation:

[(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4)

= (5t-14)(t-4)

We have the first term:
t^2+3t-8-t^2+2t+6=5t-14
so we get
[(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4)

= (5t-14)(t-4)

(5t-14)(t-4)=5t^2-14t-20t+56
Combining like terms, we get:
5t^2-34t+56