How do you factor # 2x^2+5x=8#?

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Answer 1 · 2018-06-07T21:35:19

#x=(-5+-sqrt(89))/(4)#

#2x^2+5x=8#

#2x^2+5x-8=0#

At this point you cannot factor directly or by grouping so you must either complete the square or use the quadratic formula.

#ax^2+bx+c#

#x=(-b+-sqrt(b^2-4ac))/(2a)#

#x=(-5+-sqrt(5^2-4*2*-8))/(2*2)#

#x=(-5+-sqrt(89))/(4)#