An object with a mass of #12 kg# is on a surface with a kinetic friction coefficient of # 15 #. How much force is necessary to accelerate the object horizontally at # 1 m/s^2#?

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Answer 1 · 2018-06-08T12:45:54

The force is #=1776N#

The acceleration is #a=1ms^-2#

The mass of the object is #m=12kg#

Apply Newton's Second Law to calculate the force

#F-F_r=m*a=12*1=12N#

The acceleration due to gravity is #g=9.8ms^-2#

The normal force (reaction) is #N=mg=12*9.8=117.6N#

The coefficient of kinetic friction is #mu_k=15#

The frictional force is

#F_r=Nmu_k=117.6*15==1764#

The force is

#F=12+F_r=12+1764=1776N#