How do you factor x+1+2x^2?

1 Answer
Jun 11, 2018

x+1+2*x^2=(x+(1/2+-sqrt(2)/(2)))*(x-(1/2+-sqrt(2)/(2))

Explanation:

The Quadratic Formula: For ax^2" + bx + c = 0, the values of x (factors) which are the solutions of the equation are given by:
x=(b+-sqrt(4*a*c))/(2*a)

Here, a=2, b=1 and c=1, so
x=(1+-sqrt(4*2*1))/(2*2)

=(1+-2*sqrt(2))/(4)

=1/2+-sqrt(2)/(2)

You can then factor as follows, using the two factors found:

-> x+1+2*x^2=(x+(1/2+-sqrt(2)/(2)))*(x-(1/2+-sqrt(2)/(2))