Question

How do you find the y intercept, axis of symmetry and the vertex to graph the function `f(x)=3x^2+1`?

Answer 1

`y = 1`
`x = 0`
`(0,1)`

Explanation:

The y-intercept is the point where `x = 0`. 'y' is the same as the `f(x)` of the expression.
`y = 3x^2 + 1` ; `y = 3(0)^2 + 1` ; `y = 1`

The vertex is the min/max of the function, which is the same as the y-intercept in this case: `(0,1)`
It is the point were the first derivative of the function is zero.
`0 = 6x`; `x = 0`
The axis of symmetry is the line in the middle of the curve, `x = 0`