How do you find the axis of symmetry, graph and find the maximum or minimum value of the function #f(x)=-4(x+1)^2+1#?

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Answer 1 · 2018-06-15T15:02:31

Has a maximum at #(-1,1)#

axis of symmetry #=-1#

This quadratic is in vertex form:

#y=a(x+h)^2+k#

#a>0# has min at vertex
#a<0# has max at vertex

vertex #=(-h,k)#

axis of symmetry #=-h#

Has a maximum at #(-1,1)#

axis of symmetry #=-1#

graph{-4(x+1)^2+1 [-10.08, 9.92, -6.28, 3.72]}