Question

How do you graph `f(x)=4(2^x)+1` and state the domain and range?

Answer 1

Dom(f)= R
Range(f)={y|1<y}

Explanation:

`4(2^x)+1`
`=(2^2)(2^x)+1`
`=2^(x+2)+1`

graph of `f(x)=4(2^x)+1` is
vertical shift=-2
horizontal shift=1

shift graph of `f(x)=2^x` to left 2 units and upward 1 unit.