How do you solve #3x^2-10x+3=0#?

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Answer 1 · 2018-06-19T00:45:23

See a solution process below:

We can factor the left side of the equation as:

#(3x - 1)(x - 3) = 0#

Now, solve each term on the left side of the equation for #0#

Solution 1:

#3x - 1 = 0#

#3x - 1 + color(red)(1) = 0 + color(red)(1)#

#3x - 0 = 1#

#3x = 1#

#(3x)/color(red)(3) = 1/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 1/3#

#x = 1/3#

Solution 3:

#x - 3 = 0#

#x - 1 + color(red)(3) = 0 + color(red)(3)#

#x - 0 = 3#

#x = 3#

The Solution Set Is:

#x = {1/3, 3}#