How do you find the amplitude and period of #y=2cottheta#?

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Answer 1 · 2018-06-20T05:26:19

As below.

#y = A sin (Bx - C) + D#

#y = 2 cot theta#

#A = 2, B = 1, C = D = 0#

#"Amplitude of cotangent function is " color(brown)(" NONE"#

#"Period " = (pi) / |B| = pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{2 cot x [-10, 10, -5, 5]}