How do you solve the following system of equations?: #4x – 5y = 14 , 2x + 15y = -4#?

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Answer 1 · 2018-06-20T09:21:18

#x = 4(127/140), y = 22/35#

#4x - 5y = 14, " Eqn (1)"#

#2x + 15y = -4, " Eqn (2)"#

#4x - 4x - 5y - 30y = 14 + 8#, #color(red)("Eqn (1) - 2 * Eqn (2)"#

#-35y = 22 " or " y = -(22/35)#

Substituting value of y in Eqn (1),

#4x - 5*(22/35) = 14#

#4x = 14 + 5(22/35) = (490 + 197) / 35#

#x = (687 / 140)#