How do you expand #(2x^3+1)^5#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Sonnhard Jun 20, 2018 #1+10x^3+40x^6+80x^9+80x^12+32x^15# Explanation: Use the formula #(a+b)^5=a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 4817 views around the world You can reuse this answer Creative Commons License