How do you expand #(y+x)^4#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Sonnhard Jun 20, 2018 #x^4+4x^3y+6x^2y^2+4xy^3+y^4# Explanation: since #(x+y)^2=x^2+2xy+y^2# we can write #(x^2+2xy+y^2)(x^2+2xy+y^2)=x^4+x^2y^2+2x^3y+x^2y^2+y^4+2xy^3+2x^3y+2xy^3+4x^2y^2# This is the same like above! Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 5587 views around the world You can reuse this answer Creative Commons License