Question

How do you solve the following linear system: #4x-y=-4 , 3x+3y=-18 #?

Answer 1

`x=-2` and `y=-4`

Explanation:

`3*(4x-y)+3x+3y=3*(-4)+(-18)`

`12x-3y+3x+3y=(-12)+(-18)`

`15x=-30`, so `x=-2`

Hence,

`4*(-2)-y=-4`

`-8-y=-4`

`y=(-8)-(-4)=-4`