How do you multiply $4 (2 x^{2} + 3 x^{2} y + 5 x y^{2} + 3 y^{2})$ $4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)$ ?

Question

How do you multiply $4 (2 x^{2} + 3 x^{2} y + 5 x y^{2} + 3 y^{2})$ $4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)$ ?

2 Answers

Impact of this question

1823 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-22T00:24:56

$8 x^{2} + 12 x^{2} y + 20 x y^{2} + 12 y^{2}$ $8x^2+12x^2y+20xy^2+12y^2$

Explanation:

Since we have no variables outside the parenthesis, we can just multiply the $4$ $4$ by every coefficient on the variables. We get

$8 x^{2} + 12 x^{2} y + 20 x y^{2} + 12 y^{2}$ $8x^2+12x^2y+20xy^2+12y^2$

Hope this helps!

Answer 2 · 2018-06-22T00:50:22

$8 x^{2} + 12 x^{2} y + 20 x y^{2} + 12 y^{2}$ $8x^2 + 12x^2y + 20xy^2 + 12y^2$

Explanation:

$4 (2 x^{2} + 3 x^{2} y + 5 x y^{2} + 3 y^{2})$ $4(2x^2 + 3x^2y + 5xy^2 + 3y^2)$

Distribute (multiply) the $4$ $color(blue)4$ to everything inside the parenthesis:
$8 x^{2} + 12 x^{2} y + 20 x y^{2} + 12 y^{2}$ $8x^2 + 12x^2y + 20xy^2 + 12y^2$

Hope this helps!

Science

Math

Humanities

... and beyond

How do you multiply $4 (2 x^{2} + 3 x^{2} y + 5 x y^{2} + 3 y^{2})$ $4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you multiply 4(2x2+3x2y+5xy2+3y2)4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you multiply $4 (2 x^{2} + 3 x^{2} y + 5 x y^{2} + 3 y^{2})$ $4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)$ ?