How do you multiply $4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)$ ?

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Answer 1 · 2018-06-22T00:24:56

$8x^2+12x^2y+20xy^2+12y^2$

Since we have no variables outside the parenthesis, we can just multiply the $4$ by every coefficient on the variables. We get

$8x^2+12x^2y+20xy^2+12y^2$

Hope this helps!

Answer 2 · 2018-06-22T00:50:22

$8x^2 + 12x^2y + 20xy^2 + 12y^2$

$4(2x^2 + 3x^2y + 5xy^2 + 3y^2)$

Distribute (multiply) the $color(blue)4$ to everything inside the parenthesis:
$8x^2 + 12x^2y + 20xy^2 + 12y^2$

Hope this helps!

How do you multiply 4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)?