How do you multiply #4 (2x^2 + 3x^2 y + 5xy^2 + 3y^2)#?

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Answer 1 · 2018-06-22T00:24:56

#8x^2+12x^2y+20xy^2+12y^2#

Since we have no variables outside the parenthesis, we can just multiply the #4# by every coefficient on the variables. We get

#8x^2+12x^2y+20xy^2+12y^2#

Hope this helps!

Answer 2 · 2018-06-22T00:50:22

#8x^2 + 12x^2y + 20xy^2 + 12y^2#

#4(2x^2 + 3x^2y + 5xy^2 + 3y^2)#

Distribute (multiply) the #color(blue)4# to everything inside the parenthesis:
#8x^2 + 12x^2y + 20xy^2 + 12y^2#

Hope this helps!