How do you find the product #(g-2)(g+11)#?

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Answer 1 · 2018-06-24T13:43:40

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(g) - color(red)(2))(color(blue)(g) + color(blue)(11))# becomes:

#(color(red)(g) xx color(blue)(g)) + (color(red)(g) xx color(blue)(11)) - (color(red)(2) xx color(blue)(g)) - (color(red)(2) xx color(blue)(11))#

#g^2 + 11g - 2g - 22#

We can now combine like terms:

#g^2 + (11 - 2)g - 22#

#g^2 + 9g - 22#

Answer 2 · 2018-06-24T13:44:46

#g^2+11g-2g-22#

#=g^2+9g-22#