How do you solve #x+12<=5# or #3x-21>=0#?

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Answer 1 · 2018-06-25T19:26:53

#x<=-7# or #x>=7#

First you have to - the constant (the number that doesn't multiply by x)

Then divide by the coefficient

#3x-21>=0#

constant = -21

#3x-21--21>=-21#

#3x>=-21#

coefficient is 3

#(3x)/3>=(-21)/3#

#x>=-7#

Answer 2 · 2018-07-05T23:19:12

#x<=-7# or #x>=7#

Let's start with our first inequality and subtract #12# from both sides to get

#x<=-7#

For our second inequality, we can add #21# to both sides to get

#3x>=21#

Our last step would be to divide both sides by #3#. We get

#x>=7#

Therefore our solution set for both of these inequalities is

#x<=-7# or #x>=7#

Hope this helps!