How do you solve this system of equations: #y= 2x - 7 , 3x + y = 8#?

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Answer 1 · 2018-06-25T23:14:39

#(3,-1)#

We already have #y# solved for in terms of #x#, so we can plug this value into the second equation. This gives us

#3x+color(steelblue)(2x-7)=8#

Note that what I have in blue is #y#. This simplifies to

#5x-7=8#

Adding #7# to both sides gives us

#5x=15#

Dividing both sides by #5#, we get

#color(blue)(x=3)#

To solve for #y#, we can plug this value of #x# into the first equation

#y=2x-7#

#y=2(3)-7=6-7=color(steelblue)(-1)#

The solution of these two equations is at the point

#(3,-1)#

Hope this helps!