What is the frequency of f(theta)= sin 12 t - cos 5 t ?

1 Answer
Jun 28, 2018

Period: 2pi
Frequency: 1/(2pi)

Explanation:

Period of sin (12t) --> (2pi)/12 = pi/6
Period of cos (5t) --> (2pi)/5
Period of f(t) --> least common multiple of pi/6 and (2pi)/5

pi/6 .........x(6)(2) ..... --> 2pi

(2pi)/5 .........x (5) ......... --> 2pi

Period of f(t) is P = 2pi
Frequency = 1/P = 1/(2pi)