How do you find the zeros by rewriting the function #y=2x^2-26x+24# in intercept form?
1 Answer
Jun 28, 2018
Explanation:
#"the intercept form is "y=a(x-p)(x-q)#
#"where p and q are the x-intercepts"#
#"to obtain this form factor the quadratic"#
#"to obtain the zeros set y = 0"#
#2x^2-26x+24=0#
#"divide all terms by 2"#
#x^2-13x+12=0#
#"the factors of "+12" which sum to "-13"#
#"are "-1" and "-12#
#(x-1)(x-12)=0larrcolor(blue)"in intercept form"#
#"equate each factor to zero and solve for "x#
#x-1=0rArrx=1#
#x-12=0rArrx=12#