How do you multiply #(3x+8y)(x-2y)#?
1 Answer
Jul 2, 2018
Explanation:
#"each term in the second factor is multiplied by each term"#
#" in the first factor"#
#(color(red)(3x+8y))(x-2y)#
#=color(red)(3x)(x-2y)color(red)(+8y)(x-2y)larrcolor(blue)"distribute"#
#=3x^2color(blue)(-6xy)color(blue)(+8xy)-16y^2larrcolor(magenta)"collect like terms"#
#=3x^2+2xy-16y^2#
