How do you graph x+5y=5 using intercepts?

4 Answers

Given function

x+5y=5

\frac{x}{5}+\frac{5y}{5}=1

x/5+y/1=1

The above line has x-intercept =5

y-intercept =1

i,e, the line intersects the coordinate axes at the points (5, 0) & (0, 1)

Now, specify the points (5, 0) & (5, 0) & join these points to get plot of given straight line

Jul 3, 2018

Please see below.

Explanation:

First find the x-intercept by putting y=0 i.e. x=5, which gives us point (5,0)

then find y-intercept by putting x=0 i.e. 5y=5 or y=5/5=1, giving us another point (0,1).

Joining two points gives us the graph of x+5y=5, as shown below

graph{(x+5y-5)(x^2+(y-1)^2-0.01)((x-5)^2+y^2-0.01)=0 [-3.42, 6.58, -1.42, 3.58]}

Jul 3, 2018

Use two arbitrary values for x. For example, find the intercept with y if x=0.

0+5y=5
5ycolor(red)(/5)=5color(red)(/5)
y=1

Now you know one of the intercepts is (0,1). Continue using another random x value. Let's try x=5.

cancel(5color(red)(-5))+5y=5color(red)(-5)
5ycolor(red)(/5)=0color(red)(/5)
y=0

The second intercept is (5,0).

Using these two intercepts, you can map out an x-axis and y-axis on some graph paper; draw these two intercepts and connect a line through them.

Jul 3, 2018

As below

Explanation:

x + 5y = 5

5y = -x + 5

y = -x/5 + 1

Y-intercept = 1#

X-intercept when y = 0

x/5 = 1

X-intercept = 5#

Two points are (5, 0), (0, 1)

graph{-x/5 + 1 [-10, 10, -5, 5]}