Question

What is the net area between `f(x)=ln(x^3-x+2)/x^2` in `x in[1,2]` and the x-axis?

Answer 1

Area `~~0.601`

Explanation:

The net area of a function `f` in the interval `[a,b]` is given by `A=int_a^bf(x)dx`.
`A=int_1^2ln(x^3-x+3)/x^2dx`
From wolfram alpha, we have `A~~0.601`