How do you find the amplitude and period of #y= 2sin(pi*x)#?

Question

6021 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-04T13:44:15

#2# & #2#

The periodic function #y=2\sin(\pi x)#

Amplitude #=2#

Period #={2\pi}/ \pi=2#

Answer 2 · 2018-07-04T13:48:12

Amplitude = 2, Period = 2#

#y = A sin (Bx - C) + D#

Given #y = 2 sin (pi x)#

#A = 2, B = pi, C = D = 0#

Amplitude #= |A| = 2#

Period #= (2pi)/|B| = (2pi) / pi = 2#

Phase Shift # = -C / B = 0#

Vertical Shift # = D = 0#