How do you solve #7(x-2)<-5#?

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Answer 1 · 2018-07-05T20:51:52

#x<9/7#

Dividing both sides by #7# we get

#x-2<-5/7#

adding #2# on both sides we get

#x<-5/7+14/7# (Notice #14/7=2#)

and we have

#x<9/7#

Answer 2 · 2018-07-05T22:19:37

#x<9/7#

Let's distribute the #7# to both terms on the left to get

#7x-14< -5#

Next, let's add #14# to both sides to get

#7x<9#

Dividing both sides by #7#, we get

#x<9/7#

Hope this helps!