Question

How do you write the cartesian equation for `r=1-3cosx`?

Answer 1

As below

Explanation:

`x = r cos theta, y = r sin theta, x^2+y^2=r^2`

`r = 1 - 3 cos x`

`sqrt(x^2 + y^2) = 1 - (3 x) / sqrt(x^2 + y^2)`

`x^2 + y^2 = sqrt(x^2 + y^2) - 3x`